Question

when 8 times a number is added to it's square we get 8 . find the number by making the equation properly?

Answer 1

I think your question is :

when 7 times a number is added to it's square we get 8 . find the number by making the equation properly?

Answer:

According to the correction required number is 1.

Step-by-step explanation:

According to the question let the required number be a,

It is given in the question that when 7 times a number is added to it's square we get 8.

Now,

7 times of the number = 7a

Square on the number = a^2

Adding 8 times of the number to the square of the same number : 7a + a^2

According to the question, result is 8.

So,

= >  7a + a^2 = 8

= >  a^2 + 7a = 8

= >  a^2 + 7a - 8 = 0

= >  a^2 - a + 8a - 8  = 0

= >  a( a - 1 ) + 8( a - 1 ) = 0

= > ( a - 1 ) ( a + 8 ) = 0

= > a = 1 or - 8

Taking positive value.

Therefore, required number is 1.