Question

When 9.65 coulombs of electricity is passed through a solution of silver nitrate (atomic mass of ag?

Answer 1

Explanation:

question_answer When 9.65 coulombs of electricity is passed through a solution of silver nitrate (atomic weight of. taking as 108) the amount of silver deposited is [EAMCET 1992; KCET 2000] A) 10.8 mg.

Answer 2

When 9.65 coulombs of electricity is passed through a solution of silver nitrate, the amount of silver deposited is 0.0108gm

According to the Faraday's Law of electrolysis, we know that,

w = (m*I*t)/nF

where w is the weight deposited,

m is the molar mass of Ag (108 gm)

I is the current passed

t is time elapsed

n is the number of moles (1)

F = Faraday's constant = 96500

I*t = 9.65 C

Putting the respective values, we get

w = (108*9.65)/(1*96500) gm

= 0.0108 gm

This is the required answer.