Question

when 90 gram of water is mixed with 300 gram of Acetic Acid the total number of moles will be ​

Answer 1

Answer:

5 moles

Explanation:

acetic acid=CH3COOH=300g

water=H2O=90g

if we added water in acetic acid the reaction is,

CH3COOH+H2O=CH3COO+H3O

total mass as per given=390g

molecular mass of CH3COO+H3O

12+3+12+16+16+3+16=78g

we know that number of moles=

given mass /molar mass

390g/78g=5

Answer 2

Answer:

answer is 10

Explanation:

bcoz

total no moles =given mass / mol. mass

and for these two, total no.of moles is the sum  of these

i.e.,

W1/M1 + W2/M2

no moles of water

= 90/18

= 5

no of moles of acetic acid

= 300/60

= 5

∴ Total no moles = no.of moles of water + no of moles  of acid

                                                       = 5+5

                                                          =10.