Question

When 90g of water is mixed with an equal amount of liquid of density 1.8 g/cm3

, the density

of the mixture becomes 1.5g/cm3

. Calculate the decrease in volume​

Answer 1

Explanation:

¶=m/v

1.8=90/v1

v1=50cm3

also m1=m2

¶1/¶2=[v2/v1]

1.8/1.5=v2/50

v2=60

decrease in volume=[50-60]/50

decrease in volume=[10/50]×100=20%decrease