Question

when a=0 b=-1,find value of 2a2b+2ab2+ab

Answer 1

$If \: a = 0 \: and \: b = -1 \: then$

$The \: value \: of \: 2a^{2}b+2ab^{2}+ab \\= a( 2ab + 2b^{2} + b ) \\= 0 \times ( 2ab + 2b^{2} + b ) \\= 0$

Therefore.,

$\red {The \: value \: of \: 2a^{2}b+2ab^{2}+ab}\green {= 0 }$

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Answer 2

Answer:

0

Step-by-step explanation:

2a2b + 2ab2 + ab

Putting a = 0, b = – 1, we get,

= (2 × 0 2 × -1) + (2 × 0 × (-1) 2 ) + (0 × -1)

= 0 + 0 + 0

=0

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