Question

When a 12 ∨ battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.

Answer 1

Answer:

We have potential difference (V) = 12V

Electric current (I)=2.5 mA= 2.4×10-3

According to Ohm’s Law (V) = IR

Or R = V/I

R=12/2.5×10^-3

=4.8×10^3

=4.8kwatt

Answer 2

Answer:

R = 4800 Ω

Explanation:

$V=12v$

$I=2.5mA=2.5\times10^{-3} \times10 = 25\times 10^{-4}$

$R= ?$

$R= \dfrac{V}{I}$

$R=\dfrac{12}{25\times10^{-4}}$

$R=\dfrac{12\times 10^{4}}{25}$

$R=12 \times \dfrac {10000}{25}$

$R =4800$

Therefore, R = 4800 Ω