Question

When a 12 v battery is connected across an unknown resistance where is a current of 2.5 ma?

Answer 1

v=ir ; 12=25r/10000;r=4800

Answer 2

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According to Ohm’s law,

V = IR

=v/I

Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,

=12/ 0.0025 = 4800 Ω = 4.8 kΩ

I hope, this will help you___❤❤

Thank you

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