When a 12 V battery is connected across an unknown resistor, there is a current of 2.5 mA the circuit. Find the value of resistance of the resistor.
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We have potential difference (V) = 12V
Electric current (I)=2.5 mA= 2.4×10-3
According to Ohm’s Law (V) = IR
Or R = V/I
R=12v/2.4×10^-3
=12v×10^3/2.4
=120×10^3/24
=4.8×10^3
resistance is 4.8×10^3ohm
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