When a 12 V battery is connected across an unknown resistor , there is a current of 2.5 mA in a circuit. Find the value of the resistance of the resistor
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Answer:
from John's law
v=ir
12=2.5×10^-3×r
12=2.5/10^3×r
12×10^3/2.5=r
4800=r
or 4.8×10^3
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