when a 12 volt battery is connected across an unknown resistor there is a current of 2.5 m a in the circuit find the value of the resistance of the register
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We have potential difference (V) = 12V
Electric current (I)=2.5 mA= 2.4×10-3
According to Ohm’s Law,
(V) = IR
Or R = V/I
4.8 × 10^3 is the Answer
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Answer:
R=V/I
R=12/2.5
=4.8 ohm
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