Question

when a 12 volt battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. find the value of the resistance of the register

Answer 1

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Here's ur answer

Solution:
We have potential difference (V) = 12V
Electric current (I)=2.5 mA= 2.5×10-3

According to Ohm’s Law (V) = IR
Or R = V/I

$r = \frac{12V}{25 \times {10}^{ - 3}A } \\ = 4.8 \times {10}^{ 3}$

=4800ohm

Answer 2

ANSWERS :-


GIVEN ,

potential difference (V) = 12 volts

electric current (l) = 2.5 mA

= 2.5 * 10^-3


we know ,

V = IR

R = v/l = 12/2.5 * 10^-3

= 12 *10 / 25 *10^-3

= 120 /25 * 10^-3

= 120 * 10^3/ 25

= 4.8 * 10³ ohm


Resistance = 4.8 * 10^3 ohm


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