Question

When a 12g mixture of carbon and sulphur is burnt in air then a mixture of co2 and so2 is produced in which the number of moles of so2 is half that of co2 the mass of the carbon in the mixture?

Answer 1

Answer: 5.14 grams the mass of the carbon in the mixture

Explanation:

Let the mass of $C$ be x grams

Mass of $S$ be (12 - x )grams

Mass of the mixture = 12 grams

$\frac{1}{2}n_{\text{moles of}C}=n_{\text{moles of}S}$

$\frac{1}{2}\times \frac{x grams}{12 g/mol}=\frac{(12-x)g}{32 g/mol}$

On solving for x, we get :

x = 5.14 grams

5.14 grams the mass of the carbon in the mixture

Answer 2

Answer:

5.14 gm

Explanation:

See the answer above me : )