WHEN A 12V BATTERY IS CONNECTED ACROSS AN UNKNOWN RESISTOR ,A CURRENT OF 2.5 mA FLOWS THROUGH THE CIRCUIT. CALCULATE THE VALUE OF RESISTANCE OF THE RESISTOR.
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Answered by
3
PD= 12V
I = 2.5 mA = 0.0025 A
By Ohm's Law V=IR
R=V/I
12 V ÷ 0.0025 A = 4800 ohm
I = 2.5 mA = 0.0025 A
By Ohm's Law V=IR
R=V/I
12 V ÷ 0.0025 A = 4800 ohm
Answered by
7
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According to Ohm’s law,
V = IR
=v/I
Here, V = 12 V and I = 2.5 mA = 0.0025 A Therefore,
=12/ 0.0025 = 4800 Ω = 4.8 kΩ
I hope, this will help you___❤❤
Thank you
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