When a 15V battery is connected across a resistor of 6Ω, the amount of charge passing through it
per second is
[A] 90 C [B] 2/3 C [C] 2.5 C [D] 9 C
Answers
Answered by
1
Answer:
c - 3.5
Explanation:
as
V = IR
15 = I × 6
15/6 = I
2.5= I
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