Question

when a^2+b^2+3c^2=250 and ab+bc+ca=3 find the value of a+b+c​

Answer 1

Answer:

It is given that,

a²+b²+c²=250

ab+bc+ac=3

squaring on the both sides,

(a+b+c)²=a²+b²+c²+2(ab+bc+ac)

(a+b+c)²=250+6=256

a+b+c=16

Step-by-step explanation:

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