Question

when a 20V battery is connected to an air capacitor a charge of 30 mC is obtained on the capacitor then a charge of 75 mC is obtained . Calculate (1)dielectric constant of the oil ,(2)the energy contained in the oil capacitor​

Answer 1

k =2.5

I hope this might help you

Answer 2

Answer:

V= 20 V

Q′=C′V′

C′=30×10^-6/20

C′=3×10^-6/2

Q=CV

C= 75×10^-6/20

C=15×10^-6

C/C′=K

Where K is dielectric constant of the oil

K= 15×2×10^-6/4×3×10^-6

K=2.5

2]

U=1/2CV^2

U=1/2×15×10^-6/4×20×20

U=75×10^-5

U=7.5×10^-4 J