Question

When a 22 ohms resistance is connected across its terminals a potential difference 2.2V is produced. Find the internal resistance and lost volt of the cell... Please solve this sum..This sum is from Current Electricity chapter...Class 10​..Brainly friends please help me to solve this sum...​

Answer 1

Answer:

1.11 ohms

Explanation:

P.D.=2.2volts , this is the EMF of the cell.

Now when the circuit is closed and a current is flowing through the circuit then the P.D.=1.8V

Thus the total resistance of the circuit is R+r=5+rohms

So, the current in the circuit is i=(

5+r

2.2

hence the PD across the internal resistance.

Given that,

5+r

2.2

)=2.2−1.8 as the drop in the potential across the battery is due the P.D. across the internal resistance.

So,

r(

5+r

2.2

)=0.4

1.8r=2

r=1.11ohms

Answer 2

Explanation:

P.D.=2.2volts , this is the EMF of the cell.

Now when the circuit is closed and a current is flowing through the circuit then the P.D.=1.8V

Thus the total resistance of the circuit is R+r=5+rohms

So, the current in the circuit is i=(

5+r

2.2

hence the PD across the internal resistance.

Given that,

5+r

2.2

)=2.2−1.8 as the drop in the potential across the battery is due the P.D. across the internal resistance.

So,

r(

5+r

2.2

)=0.4

1.8r=2

r=1.11ohms