Question

when a 22V battery is connected across a resistor , 2.2mA current flows in the circuit . find the resistance of the resistor.

Answer 1

v=ir=>22v =2.2r=>r= 22/2.2=> 110ohm

Answer 2

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According to Ohm’s law,

V = IR

=v/I

Here, V = 22 V and I = 2.2mA = 0.0022 A Therefore,

=22/ 0.0022= 10000 Ω = 10 kΩ

I hope, this will help you___❤❤

Thank you

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