Question

when a=3 b=0 c=-2 then find the value of
1)ab+2bc+3ca+4abc
2)asquare + bsquare+csquare+3abc

Answer 1

Step-by-step explanation:

1) 0

2) (3)^2+(0)^2+(-2)^2+3×3×0×(-2)

=9+0+4+0

=13

Answer 2

Answer:

1)

ab+2bc+3ca+4abc

3*0+2*0*(-2)+3*(-2)*3+4*3*0*(-2)

0+0+(-18)+0

-18

2)

asquare + bsquare+csquare+3abc

(3)square+(0)square+(-2)square+3*3*0*(-2)

9+0+4+0

13