Math, asked by chandu2065, 25 days ago

When : A=3. B=4 . C=10...

(AC)÷ 5xB x2+2-50=??

Answers

Answered by dayanidhisharma19
0

Answer:

0

Step-by-step explanation:

It is given that A=3, B=4, C = 10

Now, according to the BODMAS rule:

(AC)÷ 5xB x2+2-50

= (3x10)÷ 5x4 x2+2-50

= (6x4x2) + 2 - 50

= 48 + 2 - 50

= 50 - 50

= 0

Answered by uttambera538
0

A = 3

B = 4

C = 10

(AC) ÷ 5 × B × 2 + 2 - 50

= (3 × 10) ÷ 5 × 4 × 2 + 2 - 50

= 30 ÷ 5 × 4 × 2 + 2 - 50

= 6 × 4 × 2 + 2 - 50

= 24 × 2 + 2 - 50

= 48 + 2 - 50

= 50 - 50

= 0

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