Question

When a 4 kg mass is hung vertically on a light spring that
obeys Hooke’s law, the spring stretches by 2 cms. The
work required to be done by an external agent in stretching
this spring by 5 cms will be (g = 9.8 m/sec²)
(a) 4.900 joule (b) 2.450 joule
(c) 0.495 joule (d) 0.245 joule

Answer 1

Answer:

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