Question

When a 4 ohm resistor is connected across the terminal of 2 volts battery find the electric charge passing through the risistor per second

Answer 1

we know that
R=4 ohm
V=2 V
first find I=V/R
I=2/4=0.5Ampere
now,
I=Q/t. here t is 1 second
0.5×1=Q
so, charge is 0.5 Coulomb

Answer 2

Answer:

R=4 ohm

V=2 V

As we know I=V/R

I=2/4=0.5Ampere

So,

I=Q/t.

T=1 second

0.5×1=Q

Hence,charge is 0.5 Coulomb

HOPE IT HELPED YOU