Question

When a 4 ohm resistor is connected across the terminal of a 12 volt battery the

number of Coulomb passing through the registor for 2nd years​

Answer 1

Explanation:

here given that

R = 4ohm

v = 12volt

q = ??

from ohms law we came to know the relation between voltage and current

V = I X R

I = V/R

I = 12 / 4

I = 3 ampere

we know that current is ratio of given charge in per unit time so....

I = Q / T

Q = I X T

Here time is given two years first of all we convert it into sec so 365 × 2 × 24 × 60 x 60 = 63072000 sec

puting the value in above formula we get

Q = 3 x 63072000 = 189216000 coulomb

hoped so u got the ans ...thnks for questioning if u like the ans mark it as brainellist....

Answer 2

Answer:

Explanation:

Correct Question :-

When a 4 ohm resistor is connected across the terminals of a 12 V battery, the number of coulombs passing through the resistor per second is ?

Answer :-

Given :-

Voltage = 12 V

Resistance = 4 ohm

Solution :-

Number of coulombs means the current passing through the conductor.

We know that, I = V/R

⇒ I = V/R

⇒ I = 12/4

⇒ I = 3 coulombs

Hence, the number of coulombs passing through the resistor per second is 3 coulombs.