Question

When a 40 Vm-1 electric field is produced inside a conductor then 2 x 104 Am-2 current density
is established in it. Resistivity of the conductor is
(1) 2 x 10-3 am (2) 4 x 103 m (3) 2 x 103 m (4) 4 x 103 m​

Answer 1

Answer:

=> When a 40 Vm electric field is produced inside a conductor then 2 x 104 Am 2 current density Is established in it.

=> Resistivity of the conductor is:

Current density J = Electric field (E) / Resistivity (ρ)

ρ = E /J

= 40 / 2* 10⁴

= 20 * 10⁻⁴ Ωm

Resistivity of the conductor is 20 * 10⁻⁴ Ωm

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