Question

When a 40 vm electric field is produced inside a conductor then 2x10^4?

Answer 1

Answer:

Explanation:

Hey,

=> If you want to find Resistivity of the conductor then here is the solution of your query ..

Solution:

It is given that,

electric field, E = 40 vm

Current density, J = 2 * 10⁴

Resistivity, ρ = ?

J = E / ρ

ρ = E / J

= 40 / 2 * 10⁴

= 20 * 10⁻⁴ Ωm

Thus, the resistivity of the conductor is  20 * 10⁻⁴ Ωm.