when a 48 ohm resistor is connected across the terminals of a 6 volt battery of negligible internal resistance,the power developed in the resistor is-- a) 8.0w b) 0.75w c ) 13w d ) 0.125
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Answer:
option B is the correct answer
Explanation:
p=v^2/R
=36/48=3/4=.075
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power = v^2/ r
=> 36/48 = 0.75 w
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