Physics, asked by rohanmathias5996, 1 year ago

When a 4kg rifle is fired the 10 g bullet recieves an acceleration of 3*10^6cm/s the magnitude of the force acting on the rifle is

Answers

Answered by shifuts
3

F=m*a  = 0.010*3*10^4  =300 N

Answered by Anonymous
2

Answer:-

Force = 300 N

Explanation :-

To find :-

Find force ,

Given :-

 \bf{mass \: of \: bullet \:( m) = 10 \: g} \\  \\  \bf{acceleration \:  = 3 \times  {10}^{6}  \:  \:  \frac{cm}{ {s}^{2} } } \\  \\

Solution:-

We know that,

Force = mass × acceleration

 \implies \: f \:  = 10 \times 3 \times  {10}^{6}  \\  \\  \implies \: f = 300 \times  {10}^{5}  \\  \\  \because \: 1 \: newton \:  =  {10}^{5}  \: dyne \\  \\  \implies \: f = 300 \: newton

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