Question

When a 4ohm resistor is connected across the terminals of a 2V bettery,the number of coulomb's passing through the resistor per second is

Answer 1

Answer:-

• Resistance=R=4ohm
• Voltage=2V=V
• Current=I

Using ohms law

$\\ \sf\dashrightarrow \dfrac{V}{I}=R$

$\\ \sf\dashrightarrow I=\dfrac{V}{R}$

$\\ \sf\dashrightarrow I=\dfrac{2}{4}$

$\\ \sf\dashrightarrow I=0.5A$

• Time=t=1s
• Charge=Q=?

we know

$\boxed{\sf I=\dfrac{Q}{t}}$

$\\ \sf\dashrightarrow Q=It$

$\\ \sf\dashrightarrow Q=0.5\times 1$

$\\ \sf\dashrightarrow Q=0.5C$