when a 4V battery is connected across an unknown resister there is a current of 100mA in the circuit .The value of the resisters of the resister is ....
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Explanation:
Given:-
Voltage of battery = 4 V
Current in unknown resistance = 100 mA
=> 10-¹ A
Find:-
The value of the resistance (R).
Solution:-
Aaccording to Ohm's Law :
The current flowing through the conductor is directly proportional to the Voltage or potential difference across the ends of the terminals at constant temperature and pressure.
So,
\sf{V \:= I \:\times\: R }V=I×R
Here, R is constant
Substitute the known values in above formula
=> \sf{4\:=\:10^{-1}\:\times\:R}4=10
−1
×R
=> \sf{\dfrac{4}{10^{-1}}\:=\:R}
10
−1
4
=R
=> \sf{4\:\times\:10\:=\:R}4×10=R
=> \sf{40\:=\:R}40=R
=> \sf{R\:=\:40\:ohm}R=40ohm
•°• The resistance of the resist is 40 ohm.
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