Physics, asked by bahiya33, 4 months ago

when a 4V battery is connected across an unknown resister there is a current of 100mA in the circuit .The value of the resisters of the resister is ....​

Answers

Answered by prasanth1267
4

Answer:

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Explanation:

Given:-

Voltage of battery = 4 V

Current in unknown resistance = 100 mA

=> 10-¹ A

Find:-

The value of the resistance (R).

Solution:-

Aaccording to Ohm's Law :

The current flowing through the conductor is directly proportional to the Voltage or potential difference across the ends of the terminals at constant temperature and pressure.

So,

\sf{V \:= I \:\times\: R }V=I×R

Here, R is constant

Substitute the known values in above formula

=> \sf{4\:=\:10^{-1}\:\times\:R}4=10

−1

×R

=> \sf{\dfrac{4}{10^{-1}}\:=\:R}

10

−1

4

=R

=> \sf{4\:\times\:10\:=\:R}4×10=R

=> \sf{40\:=\:R}40=R

=> \sf{R\:=\:40\:ohm}R=40ohm

•°• The resistance of the resist is 40 ohm.

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