Question

When a 6 v battery is connected in series with resistors of 0.1 or 0.15 ohm 0.2 ma in the?

Answer 1

Rs =R1 +R2+ R3
Therefor. 0.1+0.15+0.2=0.45Ohm
V=IR
6=I0.45

$\frac{6}{45}$
600/45=10.90