When a 6 volt battery is connected in series with the resistance of 0.1 ohm 0.15 ohm 0.2 ohm 0.5 ohm and 6 ohm how much current would flow through the 0.3 ohm resistor?
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Explanation:
0.1+0.15+0.2+0.5+6=6.95
6V/6.95ohm = 0.863A
the current that would flow through the 0.3 Ω resistor will be 0.863 A.
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