Question

When a=61, b=63and c=65 then what is the value of a3+b3+C3-3ABC?

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

   (a+b+c)^3

= 1/2 (a+b+c) [(a-b)^2+(b-c)^2+(c-a)^2]

= 1/2 (61+63+65) [2^2+2^2+4^2]

= 1/2 (189) (24)

= 2268