When a 6V battery is connected across an unknown resistor, there is a current of 2mA in the circuit. Find the value of the resistance of the resistor.
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Answer:
3 kΩ
3*1000 Ω
Explanation:
V = IR
6 V = 2mA * R
R = 6/ 2 *
R = 3*1000 Ω
R = 3 kΩ
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