When A and B together can do a piece of work in 6 days and A aone can do in 8days in how many says can B alone did it?
Answers
Answer:
nagwiehwhegdhshdh
Step-by-step explanation:
BBC Grubbs finding
.
We have three conditions
A alone can do a piece of work in 6 days ……………………………………… (1)
B alone in 8 days ……………………………………… (2)
With the help of C, they completed the work in 3 days ……………………………………… (3)
so one day work done by A is = 1/6
one day work done by B is = 1/8
Complete work done DAYS by A,B, C A+B+C= 3
one day work done by them is 1/3
so we will first get one day work done by Ca
by adding one day work done of each
A +B + C =1/3
1/6+1/8+C=1/3
C = 1/3 -14/48
C= 1/24 ONE DY WORK DONE BY C
SO A and B took this work for 3200 rs but there is contribution done by C and the work completed.
from above calculations we got the per day work done by A, B,C and total per day work done by them is 1/3
so we will identify the per day work done % by A,B,C
consider x% per day work done % by A
1/3 * X% =1/6
because total work done is 1/3 and workdone by A is 1/6 so we get the % value on which A did work complete
1/3 * X% =1/6
X% = 1/6 * 3
X % = 1/2
X % = 0.5
So a has done 50% per day work complete
same for B
consider Y% per day work done % by B
1/3 * Y% =1/8
Y% = 1/8 * 3
Y% = 3/8
Y% = 37.5%
same for C
consider Z% per day work done % by C
1/3 * Z% =1/24
Z% = 1/24 * 3
Z% = 3/24
Z% = 12.5%
Total payment is 3200 rs
% share wise c will get 12.5%
3200 * 12.5% = 400 rs