When a angle is in third quadrant tanteta=3 then sinteta=
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tan Ф = 3 sin Ф/ cos Ф = 3
sin Ф = 3 cos Ф sin² Ф = 9 cos² Ф
sin ² Ф = 9 - 9 sin² Ф => sin² Ф = 0.9 => sin Ф = - √0.9
- ve because sin is -ve in 3rd quadrant 180 < Ф <= 270 degrees
sin Ф = 3 cos Ф sin² Ф = 9 cos² Ф
sin ² Ф = 9 - 9 sin² Ф => sin² Ф = 0.9 => sin Ф = - √0.9
- ve because sin is -ve in 3rd quadrant 180 < Ф <= 270 degrees
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Let the angle be 'α'
tanα = 3
w.k.t.
tanα = opp side / adj side
= 3/1
If we consider a right angled triangle having sides 3 n 1 units, then we get √10 as hypotenuse.
therefore, sinα = opp side / hypotenuse
= 3/√10
But α is in third quadrant.
therefore, sinα = -3/√10
tanα = 3
w.k.t.
tanα = opp side / adj side
= 3/1
If we consider a right angled triangle having sides 3 n 1 units, then we get √10 as hypotenuse.
therefore, sinα = opp side / hypotenuse
= 3/√10
But α is in third quadrant.
therefore, sinα = -3/√10
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