Question

When a ball is thrown in vertically upward direction with velocity 20 m/s, exactly at the same time another ball B is allowed to fall freely from height h. The magnitude of velocity of A with respect to B at time 2sec is

Answer 1

Answer:

Explanation:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at  ^2

=20(2)+0.5(−10)(2)  ^2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at  ^2

 

45=0+0.5(10)(t  ′ )  ^2

 t  ′  =3s

Total time= 3+2= 5s