When a ball is thrown in vertically upward direction with velocity 20 m/s, exactly at the same time another ball B is allowed to fall freely from height h. The magnitude of velocity of A with respect to B at time 2sec is
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Answer:
Explanation:
Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at ^2
=20(2)+0.5(−10)(2) ^2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at ^2
45=0+0.5(10)(t ′ ) ^2
t ′ =3s
Total time= 3+2= 5s
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