when a ball is thrown up vertically with velocity Vo , it reaches a maximum height of "h". if one wishes to triple the maximum height then the ball should be thrown with velocity.....
1- Vo^1/3
2-3Vo
3-9Vo
4-3/2Vo
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3) 3Vo.coz acceleration is directly proportional to velocity. as per equation
acceleration=velocity/time
=3Vo/time
distance=ut+1/2at^2
=3Vo+1/2×(3Vo/t)×t^2
=3[Vo+1/2×Vo/t×t^2]
=3×distance with velocity Vo
acceleration=velocity/time
=3Vo/time
distance=ut+1/2at^2
=3Vo+1/2×(3Vo/t)×t^2
=3[Vo+1/2×Vo/t×t^2]
=3×distance with velocity Vo
futureflame43:
oops....acceleration is directly proportional to velocity
i want full explanation
ok
now fine....plz add in brainest 4
ans
but ans is 1-3Vo^1/3
that is wrong I think
that can't be
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