Question

When a ball is thrown vertically upwards, it goes through a distance of 19.6 m. Find the initial velocity of the ball and the time taken by it to rise to the highest point. (Acceleration due to gravity, g= 9.8 m/s2) ​

Answer 1

Answer:

The initial velocity of the ball.

The total time taken of journey.

The final velocity of the ball when it strikes the ground (g = 9.8ms

−2)

Explanation:

11th

Physics

Motion in a Straight Line

Problems on Equation of Motion

A ball is thrown vertically...

PHYSICS

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Asked on December 27, 2019 by

Nilima Rajpurohit

A ball is thrown vertically upwards. It goes to height 19.6 m and then returns back to the ground, find-

The initial velocity of the ball.

The total time taken of journey.

The final velocity of the ball when it strikes the ground (g = 9.8ms

−2

)

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CALCULATOR

Enter the know values to find unknown

Acceleration

Distance

Final Velocity

v = u + a*t

Initial Velocity u

m/s

Final Velocity v

m/s

Time t

s

Acceleration a

m/s²

RESET VALUES

ANSWER

ATQ, height, s=19.6m

(i) Initial velocity, u=?

Now, when thrown vertically upwards,

Acceleration= −g=−9.8m/s

2

Also, at end point, final velocity= 0m/s

⇒v

2

=u

2

+2as

So, (0)

2

=(u)

2

+2(−9.8)(19.6)

⇒u=19.6m/s

(ii) For going upward,

v=u+at

⇒0=19.6+(−9.8)(t)

⇒t=2s

Total time= upward+ downward

⇒2+2=4s

(iii) For downward motion,

u=0m/s

v=?

a=+9.8m/s

t=2s

⇒v=u+at

=19.6m/s