Question

when a ball is thrown vertically upwards it goes through a distance of 19.6m. find(I) the initial velocity of the ball (ii) the time taken by it to rise to the highest point use g=9.8m/s2​

Answer 1

Answer:

1 u=19.6 and t=2s

Explanation:

v^2-u^2=2as

s=19.6 m a=-9.8m/s^2

v=0 and u=?

0-u^2=2*-9.8*19.6

   u^2     =19.6^2

u=19.6m/s

v=u+at

0=19.6-9.8t

19.6=9.8t

t=2s

Answer 2

Answer:

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