Question

when a ball is thrown verticaly upwards, it goes through a distance of of 19.6m. Find the initials velocity of the ball
and the time taken by it to rise to the highest point​

Answer 1

Answer:

19.6m/s, 2 sec

Explanation:

final velocity= 0m/s (thrown upwards)

s= 19.6m

taking acceleration due to gravity as -9.8m/s^2

v^2= u^2 + 2gs

0= u^2 + 2*-9.8*19.6

u^2= 19.6*19.6

initial velocity= 19.6m/s

v=u+gt

0=19.6+ (-9.8*t)

9.8t=19.6

t=2 seconds

Answer 2

Displacement of ball

S = 19.6 m

a = g = 9.8

At the topmost point, velocity v = 0

So,

According to v^2 = u^2 + 2aS

0 = u^2 - 2 x 9.8 x 19.6

u = 19.6 m/s

Time taken to reach the top

v = u + at

0 = 19.6 - 9.8t

t = 19.6 / 9.8 = 2 seconds