when a ball is vertically thrown upwards it goes to a distance of 19.6m . Find the initial velocity of the ball and the time taken by it to rise it to the highest point .(g= 9.8m/sec square)
Answers
Answer:
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Initial velocity of the ball is 19.6 m s⁻¹
Time taken by the ball to reach at height point is 2 sec
Explanation:
Given,
Highest point = 19.6 m
g = 9.8 m s⁻²
=> At highest point velocity of ball will be zero
=> As motion is upward so acceleration due to gravity will be taken as negative
By using the equation of motion v² - u² = 2 a s we can calculate the initial velocity
=> 0²- u² = 2 (-9.8) 19.6
=> - u² = - (19.6)²
=> u = 19.6 m s¹
By using equation of motion v = u + a t we can calculate the time taken by the ball to reach its highest point
=> 0 = 19.6 + (-9.8) t
=> 9.8 t = 19.6
=>
=> t = 2 sec
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