When a bar of iron 50.0cm long at 15 degree Celsius is heated in a furnace, it becomes 50.4cm . If the coefficient of linear expansion of iron is 1.1 X 10^-5 degree Celsius,find the temperature of furnace.
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ΔL = α L ΔT
(50.4 - 50.0) = 1.1 * 10⁻⁵ * 50.0 * ΔT
ΔT = 727.27 deg C
Temperature of furnace = 15 deg C + ΔT = 742.27 deg C
(50.4 - 50.0) = 1.1 * 10⁻⁵ * 50.0 * ΔT
ΔT = 727.27 deg C
Temperature of furnace = 15 deg C + ΔT = 742.27 deg C
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