when a battery is connected across a resistance of 16 ohm the voltage across the resistor is 12volt. when the same battery is connected across a resistor of 10ohm voltage across is 11volt the internal resistance of the battery is
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r=(E-V/E)*R.
r=(12-11/12)*(16+10)/2
r=(1/12)*13
r=(13/12)
r=1.08 V (appx.).
r=(12-11/12)*(16+10)/2
r=(1/12)*13
r=(13/12)
r=1.08 V (appx.).
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