Question

When a belt moves horizontally at a constant
speed of 1.5 m/s, gravel is falling on it at 5 kg /s . Then the extra power needed to drive
the belt is..

pls can anyone answer to the above question plsssss
if the answer is correct i will mark the answer as brainlest answer...
pls pls pls pls pls pls pls pls pls pls................​

Answer 1

Answer:

Velocity of belt ( v ) = 1.5 m/s

Rate at which the mass of gravel falls

= dm/dt = 5 kg/s

∴ Force acting on the gravel

F = dp/dt = dm/dt (v) = 5 × 1.5 = 7.5 N

Power needed

P = Fv = 7.5 × 1.5 = 11.25 W Ans...

Hope it helps you...