Question

when a block of mass M is suspended by a long wire of length L ,the length of the wire becomes (L+l) .the elastic potential energy stored in the extended wire is:​

Answer 1

Answer:

elastic potential energy stored =1/2 F∆L

U=1/2Mg l

Mg because F =mass ×gravity

here L is neglected because the formula is ∆L so only the elongation is considered. Hence L is neglected.