When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l) . The elastic potential energy stored in the extended by wire.
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Explanation:
Elastic potential energy stored in string (when it stretched) =1/2 kx²
(Where x is stretched length l )
=1/2×Mg/l×(l²). [ Since F = kx ]
=1/2×Mgl
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