Question

when a block of mass m on a horizontal smooth surface is subjected to a pull acting at an angle q to the horizontal ,for no motion along the vertical direction ,the expression for reaction should be​

Answer 1

Answer:

here work done is equal to the product odf displacement and the horizontal component of force like f cos(q)*s

Explanation:

let displacement is ...s

and the force applied in the horizontal direction is f cos(q)....here q is the given angle with horizontal.....

now work done is given by the following equation....w=f cos(q)*s

Answer 2

Answer:

mg-Fsinq is the correct answer