Question

When a block of wood of mass 2kg is pushed along a horizontal flat surface of a bench, the force of friction is 4N. When the block is pushed along the bench with a force of 10N, it moves with a constant

Answer 1

Answer:

acceleration of 3m/s^2

Explanation:

friction force is resisting the motion and push is supporting the motion so total supporting force will move the block so

so force with is helping in motion is

supporting force - resisting force

so

10-4=6N

so by

F=ma

6=2a

a=3m/s^2

Answer 2

Answer:

This is the answer

Explanation:

Acceleration of the body is the slope of the v-t graph.

From the graph, slope of line =

4

4−8

=−2.

So deceleration is 2 m/s

2

μg=∣a∣=2

⟹ μ=2/10=0.20