Physics, asked by ayeshaprd15, 6 months ago

When a boat is partially immersed in water, it displaced 600 kg of water. How much is the buoyant force acting on the boat in newtons?(g=10 m )

Answers

Answered by abhijeet6574
0

Answer:

For bouyant force we use the formula vρg

here we have m = 600 kg

g = 10m/s

ρ = m/ v

1000kg/ m3 = 600/ v

v = 600 / 1000 = 3/5

Bouyant force = vρg

= 3/5 × 1000 × 10

= 6000 N

Hope it helps mAtE...

Answered by ButterFliee
3

GIVEN:

  • Mass of the boat = 600 kg
  • Acceleration due to gravity = 10 m/s²

TO FIND:

  • What is the force of buoyancy of boat ?

SOLUTION:

We have given that the boat displaced 600 kg of water

It means mass of the boat = 600 kg

We know that the formula for finding the buoyant force is:-

\large{\boxed{\bf{\star \: BUOYANT \: FORCE =  Mass \times Acceleration \: due \: to \: gravity\: \star}}}

According to question:-

  • Mass = 600 kg
  • Acceleration due to gravity = 10m/

\sf{\longmapsto Buoyant \: Force = 600 \times 10 }

\bf{\longmapsto \star \: Buoyant \: Force= 6000 \: N \: \star}

  • Buoyant Force = 6000 N

Hence, the buoyant force of boat is 6000 N

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