When a bob suspended i'n train and train moving with accelerated motion?
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When the bob is suspended in the train moving with constant acceleration, the bob experiences pseudoforce . As a result is pushed upwards and backwards opposite to direction of acceleration.
I will tell you the formula considering the relationship between the angle of bob, acceleration and gravity.
Let theta be the angle made by bob with vertical.
Therefore,
tan(theta) = a/g. [a - acceleration]
[g - gravity ]
Please learn the concept of pseudoforce from your book.
In short pseudoforce is related to inertia.
Hope you will be able to understand.
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